A certain university in the United States has a student enrollment of 19,100. Mr. Hill knows the percentage of students that are male and the percentage of students that are female. To conduct the simulation, Mr. Hill has placed one hundred colored chips in a bag, using the appropriate percentages of enrolled male and female university students. Red chips represent males, and yellow chips represent females. Suppose a different student reaches in the bag, randomly selects their twenty chips, and estimates that 60% of the students are male. Based on this sample, what is a good estimate for the number of enrolled university students that are female?

7640 Students are Girls

Step-by-step explanation:

10% of all students is 1,910

We know 60% is male so we do 1910 x 6 = 11460

Now we take the total - the amount of guys

19,100 - 11460 = 7640

40% is female = 7,640

45%

40 yellow chips

Step-by-step explanation:

Total chips: 9 + 11 = 20

P(Male) = 9/20 × 100 = 45%

60% of 100

60/100 × 100

60 red

100 - 60 = 40 yellow chips

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!