Which of the following shows the graph of y = 2 l n x On a coordinate plane, a curve starts at (0, negative 2) in quadrant 4 and then increases into quadrant 1 and approaches y = 3. On a coordinate plane, a curve starts in quadrant 4 and then curves up into quadrant 1 and approaches y = 5. It crosses the x-axis at (1, 0). On a coordinate plane, a curve approaches the y-axis in quadrant 2 and then increases into quadrant 1. It crosses the y-axis at (0, 1). On a coordinate plane, a curve approaches the y-axis in quadrant 2 and then increases into quadrant 1. It crosses the y-axis at (0, 2).

The graph of y = 2ln(x) is (b) on a coordinate plane, a curve starts in quadrant 4 and then curves up into quadrant 1 and approaches y = 5. It crosses the x-axis at (1, 0).

The equation of the graph is given as:

Start by plotting the graph of .

From the graph (see attachment), we have the following highlights

From the list of given options, only option (b) describes the above highlights

Hence, the graph of y = 2ln(x) is (b)

Read more about graphs and functions at:

link

The answer to this question can be defined as follows:

Step-by-step explanation:

Given:

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .