The perimeter of a rectangular city park is 1,428 feet. The length is 78 feet more than twice the width. Find the length and width of the park.

Length =  502 ft

Width = 212 ft

Step-by-step explanation:

Recall the formula for the perimeter of a rectangle of length "L" and width "W":

Perimeter = 2 L + 2 W = 1428  ft

Now, since the length is 78 ft more than twice the width, then we can write this in mathematical form as:

L = 2 W +78

so, 2 W = L -7 8

and now replace "2 W" with it equivalent  "L - 78"  in the first perimeter equation and solve for "L":

2 L + L - 78 = 1428

3 L = 1428 + 78

3 L = 1506

L = 1506/3

L = 502 ft

Then the width W can be obtained via:

2 W = L - 78

2 w = 502 -78

2 W = 424

w = 212 ft

answer: '

the distance between points l and m

step-by-step explanation:

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