A person x inches tall has a pulse rate of y beats per minute, as given approximately by yequals600 x Superscript negative 1 divided by 3 for 30 less than or equals x less than or equals 75. What is the instantaneous rate of change of pulse rate for the following heights? (A) 39-inches (B) 71-inches What is the instantaneous rate of change of pulse rate for a 39 inch tall person?

a) 5.13beats/min

b) 2.82 beats/min

Step-by-step explanation:

Given the pulse rate of a person modelled by the equation y = 600x^-1/3 for 30≤x≤75

If the height is 39inches, the instantaneous rate of change of pulse rate for the heights will be expressed as;

y = 600(39)^-1/3

y = {600(1/39)}/3

y = 600/39×3

y = 600/117

y ≈ 5.13beats/min

The instantaneous rate for a 39 inches tall person is 5.13 beats per min

b) For a 71inches tall person, the beat rate will be expressed as;

y = 600(71)^-1/3

y = {600(1/71)}/3

y = 600/71×3

y = 600/213

y ≈ 2.82 beats per minute

The instantaneous rate for a 71 inches tall person is 2.82 beats per min

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

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step-by-step explanation:

the true ones are a b and d