The digits in the tens place of a two-digit number are 3 more than the digits in the unit place. If the digit at the unit place be ‘b', then the number is a) 11b + 30 b) 10b + 30 c) 11b + 3 d) 10b + 3

A

Step-by-step explanation:

We are told that the number at the unit place is 3 less than the number at the tens place.

So if the number at the units place is b, then the number at the tens place is 10(b+ 3)

So the number is thus;

10(b + 3) + b

= 10b + 30 + b = 11b + 30