Anumeha is mowing lawns for a summer job. For every mowing job, she charges an initial fee of $ 10 $10dollar sign, 10 plus a constant fee for each hour of work. Her fee for a 5 55-hour job, for instance, is $ 35

F(t) = 10 + 5(t)

Step-by-step explanation:

The complete question is as follows;

Anumeha is mowing lawns for a summer job. for every mowing job, she charges an initial fee of \$10$10dollar sign, 10 plus a constant fee for each hour of work. her fee for a 555-hour job, for instance, is \$35$35dollar sign, 35. let f(t)f(t)f, left parenthesis, t, right parenthesis denote anumeha's fee for a single job fff (measured in dollars) as a function of the number of hours ttt it took her to complete it. write the function's formula.

Solution

We are interested in writing the function F(t) formula for the fee charged by Anumeha per job.

Now, the key to writing this function is knowing exactly the constant fee she charges on the job.

We were told that she got $35 for a 5 hour job.

Thus, the constant amount charged is as follows;

Since it’s $10 as initial fee and the constant fee is per hour;

35 = 10 + 5(x)

where x is the constant fee per hour

35 = 10 + 5x

5x = 35-10

5x = 25

x = 25/5

x = $5

This mess that she charges a constant fee of $5 per hour

So we can write the equation now.

F(t) = 10 + 5(t)

where t represents the number of hours she spent on the job

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)