Mathematics
Mathematics, 03.07.2020 05:01, ambarpena14

Given: ∆ABC –iso. ∆, m∠BAC = 120° AH ⊥ BC HD⊥ AC AD = a cm, HD = b cm Find: P∆ABH


Given: ∆ABC –iso. ∆, m∠BAC = 120° AH ⊥ BC HD⊥ AC AD = a cm, HD = b cm Find: P∆ABH

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Given: ∆ABC –iso. ∆, m∠BAC = 120° AH ⊥ BC HD⊥ AC AD = a cm, HD = b cm Find: P∆ABH
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