find the equation of the line that is perpendicular to y= -1/5x-3 and contains the point (1,2) answer all boxes please

Y = 5x -3

Step-by-step explanation:

Let's look for the gradient to solve this question for.

We are given y= -1/5x-3

Any line perpendicular to the above line will have a graient of m'.

Where mm'= -1

m = -1/5 from the line equation

So

mm'= -1

-1/5m'= -1

m' =5

For the equation of point (1,2)

(Y-y1)/(x-x1) = m'

(Y-2)/(x-1)= 5

Y-2= 5x -5

Y = 5x -3