If the perimeter of triangle ABC is 4 more than the perimeter of triangle ACD, what is the perimeter of quadrilateral ABCD? AD is 5, DC is 6, AC is unknown, AB is unknown, CB is 7.

26 units.

Step-by-step explanation:

AB + BC + AC = AC + AD + DC + 4

AC is common so

AB + BC = AD + DC + 4

AB + BC - AD - DC = 4

Substituting the given values

AB + 7 - 5 - 6 = 4

AB = 4 - 7 + 5 + 6 =  8

So the perimeter of ABCD

= AB + BC + AD + CD

= 8 + 7 + 5 + 6

= 26.

i need a diagram

step-by-step explanation:

no