What is the area of the shaded part of the circle that has a diameter of 8 mm? Use 3.14 for 4 mm
8 mm
O 16mm?
O 32mm?
O 34 24 mm
50.24 mm?

34.27 sq. mm.

Step-by-step explanation:

Area of a triangle = hb / 2

= 8 x 4 / 2

= 32 / 2 = 16 mm

Area of the circle = πr^2

= π x 4^2

= 50 27 sq. mm.

Area of the shaded part

= 50.27 - 16

= 34.27 sq. mm

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this