As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.10. If the cans are currently 12 cm tall, 6 cm in diameter, and have a volume of 339.12 cm3, how much more will the new cans hold? Use 3.14 for π and round your answer to the nearest hundredth.

124.67cm³

Step-by-step explanation:

==>Given:

Dimensions of current can:

Height (h) = 12cm

Diameter = 6cm (radius = 3cm)

Volume of current can (V1) = 339.12 cm³

Dimensions of future cans to be increased multiple of 1.11:

height = 12cm × 1.11 = 13.32 cm

radius = 3cm × 1.11 = 3.33 cm

Volume of future can (V2) = πr²h = 3.14*3.33²*13.32

= 3.14*11.0889*13.32 = 463.791025

V2 ≈ 463.79 cm³

==>Find how much more would new cans hold = Volume of new can - volume of current can

= 463.79 cm³ - 339.12 cm³

= 124.67cm³

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5