A rotating light is located 13 feet from a wall. The light completes one rotation every 5 seconds. Find the rate at which the light projected onto the wall is moving along the wall when the light's angle is 10 degrees from perpendicular to the wall.

42.115 ft/s  

Step-by-step explanation:

The distance from the point closest to the light is given by

 d = (13 ft)tan(α)

where,

α=angle from perpendicular.

Since the light travels through an angle of 2π radians in 5 seconds, the angle can be represented by

 α = πt . . . . radians      

and the rate of change of α is dα/dt = π (radians/second)

The rate of change of distance is:

dd/dt = (13 ft)sec(α)²(dα/dt) = (13π)(sec(10°)²) ft/s ≈ 42.115 ft/s  

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate

just sum

10 + 10 = 20