1) 5x > 2x - 6 please help all of this are questions of their own 2) x + 3 < 8 3) x - 2 ≥ 12 4)4y < 24

1) x > -2

2) x < 5

3) x ≥ 14

4) y < 6

Step-by-step explanation:

5x > 2x - 6

5x - 2x > -6

3x > -6

x > -6/3

x > -2

x + 3 < 8

x < 8 - 3

x < 5

x - 2 ≥ 12

x ≥ 12 + 2

x ≥ 14

4y < 24

y < 24/4

y < 6

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step-by-step explanation:

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i know the way

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let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0