AA display has 666 packs of marbles with a total mass of 629\,\text{g}629g629, start text, g, end text. The packaging of each pack has a mass of \dfrac{2}{3}\,\text{g} 3 2 gstart fraction, 2, divided by, 3, end fraction, start text, g, end text and each marble has a mass of 4\dfrac{1}{2}\,\text{g}4 2 1 g4, start fraction, 1, divided by, 2, end fraction, start text, g, end text. Which equation can we use to determine mmm, the number of marbles per pack?

6\left(\dfrac{2}{3}+4\dfrac{1}{2}m\right)=6296(

3

2

+4

2

1

m)=6296, left parenthesis, start fraction, 2, divided by, 3, end fraction, plus, 4, start fraction, 1, divided by, 2, end fraction, m, right parenthesis, equals, 629 t

Step-by-step explanation:

i got this from khan

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk