Hoping to increase the chances fo reaching a performance goal, the director of a research project has assigned three separate research teams the same task. The director estimates that the team probabilities are 0.90, 0.80, 0.70 for successfully completing the task in the allotted time. Assuming that the teams work independently, what is the probability that the task will NOT be completed in time

P = 0.006

Step-by-step explanation:

If the first team have a probability of 0.9 to complete the task, we can said that the probability to not complete the task in time is 0.1. It is calculated as:

1 - 0.90 = 0.1

At the same way, the probability to not complete the task for the second and third team are 0.2 and 0.3 respectively and they are calculated as:

1 - 0.80 = 0.2

1 - 0.70 = 0.3

Finally, the the probability that the task will NOT be completed in time is the probability that any of the teams completed the task. So, it is equal to:

P = 0.1 * 0.2 * 0.3 = 0.006

its c or d   take a lucky guess my dude

the bolded word " farsighted" could be replaced with visionary.