If a coin is tossed 4 times, and then a standard six-sided die is rolled 3 times, and finally a group of two cards are drawn from a standard deck of 52 cards without replacement, how many different outcomes are possible?

4,582,656

Step-by-step explanation:

A coin is tossed 4 times,

2^4 outcomes: 16

and then a standard six-sided die is rolled 3 times, 6^3

216 outcomes:

and finally, a group of two cards is drawn from a standard deck of 52 cards without replacements

It says a “group”, so, I guess the order doesn’t matter… So it is “52 choose 2”

52*51/ (2*1) = 26*51

how many different outcomes are possible?

16*216*26*51 = 4,582,656

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.

the answer to 1/4x+5/3x-4=2-1/12x is x=3

hope this if needed hmu