X is a normally distributed random variable with the standard deviation of 4.00.Find the mean of X when 64.8%

μ = 9.504

Step-by-step explanation:

I get complete question that is x is a normally distributed random variable with a standard deviation of 4.00. find the mean of x when 64.8% of the area lies to the left of 11.02

given data

standard deviation = 4

solution

we know that that

X ∞ Normal ( μ , 4²)     ...............1

so Probability P will be express as

P ( X < 11.02 ) = 64.8%

so here

P ( Z < ) = 0.648

Z for 0.648  =  

0.379 =  

solve it we get

μ = 9.504

6 adults and 9 children went.

a + c = 15

12a + 9c = 153

12(6) + 9(9) = 153

72 + 81 = 153