Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula d = StartRoot StartFraction 3 h Over 2 EndFraction EndRoot, h greater-than-or-equal-to 0 with d being the distance they can see in miles and h being their eye-level height in feet.

3√5 miles

Step-by-step explanation:

We are given the formula as;

d = √(3h/2)

Wyatt:

His eye level is 120 ft above sea level, so;

h = 120 ft

Hence;

d = √(3 × 120/2)

d = √180

d = √(36 × 5)

d = √36 × √5

d = 6√5 miles

Shawn:

His eye level is 270 ft above sea level, so;

h = 270 ft

d = √(3 × 270/2)

d = √405

d = √(81 × 5)

d = √81 × √5

d = 9√5 miles

So to find how much farther Shawn can see to the horizon, we'll subtract the value of d of wyatt from that of shawn.

Thus;

Shawn - Wyatt = 9√5 - 6√5 = 3√5 miles

7.3

step-by-step explanation:

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus