The person who answers the question with the mathematical explanation and answer gets 65 points in total if answers correctly and marked as the brainliest so DON'T ANSWER WITH AN IDK AND GET FREE POINTS! If the area of a circle of radius 7 cm is 154 sq cm, what is the area of the shaded portion of the figure shown below?

10.5 squared centimetres.

Step-by-step explanation:

First, find the area of that sector. We are already given that the circle is 154 squared centimetres.

We are given 90 degrees (or one fourth of the circle). Thus, divide 154 by 4 to get the area of the sector (the white area).

The area of the sector is 154/4 or 38.5

We then need to find the area of the square. After that, we can subtract the sector area (the white area) from the area of the square (the total area) to find the area of the shaded section.

The area of the square is 7*7 or 49.

Thus, the shaded portion will be 49-38.5 or 10.5 squared centimetres.

10.5 cm^2

Step-by-step explanation:

The square has area s^2 = (7 cm)^2 = 49 cm^2

The area of the portion is the the area of the square minus the area of 1/4 of the circle.

Area of 1/4 of the circle = 154 cm^2 / 4 = 38.5 cm^2

Area of shaded portion = 49 cm^2 - 38.5 cn^2 = 10.5 cm^2

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.