Write the equation of a line parallel to the line 2x + 3y = 5 and passes through the point (9, -3) y = 2x – 21

y = -2/3x +3

Step-by-step explanation:

2x + 3y = 5

First we need to find the slope of this line by subtracting 2x

3y = -2x +5

Divide by 3

3y/3 = -2/3x +5/3

y = -2/3x +5/3

The slope is -2/3

Parallel lines have the same slope

We have the point (9,-3)

y = mx+b

where m is the slope and b is the m intercept

y = -2/3x+b

-3 = -2/3(9) +b

-3 = -6+b

-3+6 = -6+6+b

3 = b

y = -2/3x +3

y= -2/3x+3

Step-by-step explanation:

Given line:

Parallel line has the same slope and equation is:

using the given point (9, -3) we can find y-intercept:

So the required equation is:

4x and 6y

im not sure though

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.