What is the standard form for the quadratic function? f(x)=(x−3)2+5 f(x)=x2−4 f(x)=x2+14
f(x)=x2−6x+14
f(x)=x2+6x−4

x^2-6x + 14

Step-by-step explanation:

Here, we want to

write the standard form of the quadratic equation in the question.

This can be written by expanding the bracket.

F(x) = (x-3)^2 +5

F(x) = (x-3)(x-3) + 5

F(x) = x(x-3)-3(x-3) +5

F(x) = x^2 -3x-3x + 9 + 5 = x^2-6x + 14

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )