Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1. f(x) = −one half(x − 6)2 + three halves
f(x) = one half(x − 6)2 + three halves
f(x) = −one half(x + three halves)2 + 6
f(x) = one half(x + three halves)2 + 6

if im not mistaking its

step-by-step explanation:  

angle efh= angle egh

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6