Right triangle ABC is on a coordinate plane. Segment AB is on the line y = 2 and is 5 units long. Point C is on the line x = −2. If the area of ΔABC is 12.5 square units, then find a possible y-coordinate of point C. 5 6 7 8

Step-by-step explanation:

Segment AB is on the line y = 2 which is a horizontal line. Point C is on the line x = -2, which is a vertical line. These 2 lines will cross each other and form a right angle...the right angle in the right triangle in question. The formula for the area of a triangle is

The segment AB, being a horizontal line, is the base of our triangle and point C is somewhere on the height. If we can find the height of the triangle, we can add or subtract that height from y = 2 to get the possible y coordinate of point C. We already know the x coordinate (it's -2).

and

25 = 5h so

h = 5. That means that we can either add 5 to the y coordinate of 2, or we can subtract 5 from the y coordinate of 2 to get the possible y coordinate of point C.

2 + 5 = 7 so the coordinate for C could be (-2, 7) or

2 - 5 = -3 so the coordinate for C could also be (-2, -3).

Since -3 is not in our choices but 7 is, the one you want is 7.

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

child does not get an education so she can use the molla on junk