How do I solve (2x-y)(3x+y)

6x^2 -xy - y^2

Step-by-step explanation:

(2x-y)(3x+y)

FOIL

first: 2x*3x = 6x^2

outer: 2x*y = 2xy

inner: -y*3x = -3xy

last: -y^y = -y^2

Add these together

6x^2 +2xy-3xy - y^2

Combine like terms

6x^2 -xy - y^2

Step-by-step explanation:

what?

step-by-step explanation:

what do you need with. i love quadrants. can you tell me ?

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine