The areas of the sides of a rectangular box are 14 in.² squared 16 in.² and 56 in.² What is the volume of the box?

  112 in³

Step-by-step explanation:

We assume the side areas are of just one of the two sides with equal area.

Consider the areas to be a, b, c in terms of box dimensions x, y, z:

  a = xy; b = yz; c = xz

Then the product of the areas is ...

  abc = (xy)(yz)(xz) = x²y²z²

and the volume of the box is ...

  V = xyz = √(x²y²z²) = √(abc)

  V = √((14 in²)(16 in²)(56 in²)) = √(12544 in⁶)

  V = 112 in³

The volume of the box is 112 cubic inches.

The dimensions of the box could be 2 in by 7 in by 8 in.

answer: i don't understand it

step-by-step explanation: sorry

x + 4/7

step-by-step explanation:

use cymath