The temperature at 12 Noon was above zero. If it decreases at the rate of 4 degrees Per hour until midnight, at what time would the temperature be four degrees below zero?

Step-by-step explanation:

this is also unsolveable or no solution

there is not enough information to solve...

the termperator at 12 Noon (this is time) was above zero

BUT>>>>> how much above zero

o-o

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 O

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."