1. Draw a histogram from all the data. Starting at the bottom row, for each set of 10 flips, place an “x” in the column corresponding to the number of heads that set produced. Your histogram should look similar to the example below: 2. Calculate the mean and standard deviation. mean = , standard deviation = 3. Calculate the percent of the data that is within 1, 2, and 3 standard deviations of the mean. within 1 standard deviation = % within 2 standard deviations = % within 3 standard deviations = % 4. Compare your results to a normal distribution. Interpret any differences.

1. use an automatic coin flip or flip a coin 10 times for 10 sets. write down how many times you get heads out of 10.

2. mean= 4.6

SD= 3.1

3.  1. 90% 2. 100% 3. 100%

4. this is not a normal distribution

Step-by-step explanation:

1. for me i got

1   2  3  4   5  6  7  8  9  10

6  3  2   5  3  6  4  7  6   4

2. (6-4.6)^2+ (3-4.6)^2+(2-4.6)^2+(5-4.6)^2+(3-4.6)^2+(6-4.6)^2+(4-4.6)^2+       (7-4.6)^2+(6-4.6)^2+(4-4.6)^2= 24.4

Variance=2.6

24.4/2.6= 9.4

= 3.1

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.