The slope, m, of a linear equation can be found using the formula m = StartFraction y 2 minus y a Over x 2 minus x 1 EndFraction., where the x- and y-values come from two ordered pairs, and (x1, y1) and (x2, y2). What is an equivalent equation solved for y2?

y2 = m(x2-x1)+y1

Step-by-step explanation:

Given the formula for finding the slope of a linear equation to be;

m = y2-y1/x2-x1 where x and y are from the ordered pairs (x1,y1) and (x2,y2)

To get the equivalent equation for y2, we will make y2 the subject of tbw formula from the equation as shown:

m = y2-y1/x2-x1

Cross multiplying

m(x2-x1) = y2-y1

mx2-mx1 = y2-y1

Adding y1 to both sides of the equation we have;

mx2-mx1 + y1= y2-y1+y1

y2 = mx2-mx1 + y1

y2 = m(x2-x1)+y1

This gives the resulting equation to solve for y2

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