Mathematics, 28.06.2020 19:01, giajramosp2r5da
Read the proof. Given: AB ∥ DE Prove: △ACB ~ △DCE Triangle A B C is shown. Line D E is drawn inside of the triangle and is parallel to side A B. The line forms triangle D C E. We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA. We can state ∠C ≅ ∠C using the reflexive property. Therefore, △ACB ~ △DCE by the AA similarity theorem. SSS similarity theorem. AAS similarity theorem. ASA similarity theorem.
Answers: 1
Mathematics, 22.06.2019 01:00, yaxcalandreya
Given right triangle a w/a hypotenuse length of x+4 and a leg of x, and right triangle b, w/ a hypotense length of 3y and a leg length of y+4 for what values of x and y are the triangles congruent by hl?
Answers: 3
Read the proof. Given: AB ∥ DE Prove: △ACB ~ △DCE Triangle A B C is shown. Line D E is drawn inside...
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