Using factor theorem factories 2x3-x2-13x-6

p(2)=2(2)^3+(2)^-13(2)+6=16+4-26+6=0

(x-2) 2x^2+5x-3

x-2√2x^3+x^2-13x+6

2x^3-4x^2

5x^2-13x 5x^2

-3x+6-3x+6

2x^3+x^2-13x+6=(x-2) (2x^2+5x-3)

(x-2) (2x^2+6x-x-3)

(x-2) [2x(x+3)-1(x+3)]

(x-3) (x+3) (2x-2)

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8