Mathematics
Mathematics, 28.06.2020 15:01, katlian

Clara solved the equation 7 3 x = βˆ’ 2 3 as shown. 7 3 x ( 3 7 ) = βˆ’ 2 3 ( 3 7 ) x = βˆ’14 What is Clara’s error? Clara should have divided by StartFraction 3 over 7 EndFraction. Clara should have added StartFraction 7 over 3 EndFraction. Clara should have multiplied by StartFraction 7 over 3 EndFraction. The solution is Negative StartFraction 2 over 7 EndFraction, not –14.

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Clara solved the equation 7 3 x = βˆ’ 2 3 as shown. 7 3 x ( 3 7 ) = βˆ’ 2 3 ( 3 7 ) x = βˆ’14 What is Clar...

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