The height of a triangle is 4 in. Greater than twice the base. The area of the triangle is no more than 168in^2. Which inequality can be used to find the possible lengths, x, of the base of the triangle

b^2 + 2b <= 168

Step-by-step explanation:

The base is b.

The height, h, is 4 in. greater than twice the base, so the height is 2b + 4.

The area of a triangle is bh/2. We replace h with the expression for height.

A = bh/2 = b(2b + 4)/2 = (2b^2 + 4b)/2 = b^2 + 2b

The area is b^2 + 2b.

The area is no more than 168 in.^2, so it is less than equal to 168 in.^2.

b^2 + 2b <= 168

("<=" means "less than or equal to")

Since you don't show the choices, choose an inequality that is equivalent to the one just above.

i'm sure goog can you get that answer