What is the solution to StartFraction 5 over 6 EndFraction x minus one-third greater-than 1 and one-third? x > StartFraction 25 over 18 EndFraction x < StartFraction 25 over 18 EndFraction x > 2 x < 2

Correct option: third one -> x > 2

Step-by-step explanation:

Writing the inequation from the sentence in the question, we have:

To solve this inequation we can do the following steps:

So the correct option is the third one: x > 2

a² + b²= c²

24² + 7² = c²

c= 25

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for