Help please i’ll give 55 points

1. 100 - 12y = 16

2. b * (15 + 37) = 156

3. 27 + 12z = 87

4. 135/(5c) = 3

5. w^2 * (12/4) = 300

6. 12d / (25-19) = 4

7. 5x + 13 = 68

Step-by-step explanation:

1.

The product of y and 12 is "12y", so the difference of 100 and this product is "100 - 12y". The value of y is 7, so we have:

100 - 12*7 = 100 - 84 = 16

2.

The sum of 15 and 37 is "15 + 37", and b times this sum is "b * (15 + 37)"

b is equal to 3, so we have:

3 * (15 + 37) = 3 * 52 = 156

3.

The product of z and 12 is "12z", so 27 added to this product is "27 + 12z". The value of z is 5, so we have:

27 + 12*5 = 27 + 60 = 87

4.

The product of c and 5 is "5c", so 135 divided by this product is "135/(5c)". The value of c is 9, so we have:

135/(5*9) = 135 / 45 = 3

5.

The quotient of 12 and 4 is "12/4", so w to the second power times this quotient is "w^2 * (12/4)"

The value of w is 10, so we have:

10^2 * (12/4) = 100 * 3 = 300

6.

The difference of 25 and 19 is "25 - 19", so 12 times d divided by this difference is "12 * d / (25-19)"

The value of d is 2, so we have:

12 * 2 / (25-19) = 24 / 6 = 4

7.

The product of x and 5 is "5x", so this product added to 13 is "5x + 13"

The value of x is 11, so we have:

5*11 + 13 = 55 + 13 = 68

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

i wish i could u

step-by-step explanation:

i wish i could u