The Elon Company manufactures parts for an aircraft company using three computerized numerical controlled (CNC) turning centers. The company has to decide which machines are capable of producing a specific part with design specifications of 0.0970 inch ± 0.015 inch. The machines have the following parameters: Machine 1 (mean= 0.0995, s = 0.004); Machine 2 (mean = 0.1002, s = 0.009); Machine 3 (mean = 0.095, s = 0.005). Determine which machines (if any) are capable of producing the products within the design specifications.

machine 1 with the mean  0.0995, s = 0.004  will only be capable of producing the products within the design specifications.

Step-by-step explanation:

Given that:

The company has to decide which machines are capable of producing a specific part with design specifications of 0.0970 inch ± 0.015 inch.

The upper limit of the specific part = 0.0970 inch +  0.015 inch = 0.112 inch

The lower limit of the specific part =  0.0970 inch -  0.015 inch = 0.082 inch

Th question continues by stating the following parameters for the machines.

Machine 1 (mean= 0.0995, s = 0.004);

Machine 2 (mean = 0.1002, s = 0.009);

Machine 3 (mean = 0.095, s = 0.005).

The main objective here is to determine  which machines (if any) are capable of producing the products within the design specifications.

Given that Cp is < 1

This process will be capable if Cpk is ≥ 1

To start with machine 1;

Cpk = Min[1.46, 1.04]

Cpk = 1.04

Thus this process is capable because Cpk ≥ 1  

Machine 2;

Cpk =  Min[0.67, 0.44]

Cpk = 0.44

Thus this process is not  capable because Cpk < 1  

Machine 3

Cpk =  Min[0.87, 1.13]

Cpk = 0.87

Thus this process is not  capable because Cpk < 1  

In conclusion, machine 1 with the mean  0.0995, s = 0.004  will only be capable of producing the products within the design specifications.

don't know sorry bru

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.