EJERCICIOS: En cada caso, hacer la reducción de los términos semejantes. 1. 8a + 9a 2. – 8m – m 3. 6ax+1 – 8ax+1 4. – 3ax–2 – ax–2 5. 3 ab + 1 ab 6. –14xy + 32xy 5 10 7. 4ax + 5ax 8.  1 a – 3 a 2 4 9.  5 a2b – 1 6 8 10. – 7m – 8m + 9m 11. – 5ax+1 – 3ax+1 + 6ax+1 12. 3 am – 5 am 8 4

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step-by-step explanation:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

i believe it is 0.1m because the measurement of 30.4m limits how precise you can be

you can only be as precise as the least precise measurement

you have 6 equal triangles, find the area of one of them (b*h/2) and multiply by 6

(8*4: 2)*6 =

32 cm² is your answer