The sum of the first four terms of an AP is 30 and the sum of the last four terms is 66. If the AP has 7 terms, find the first term and the common difference

2 and 3

Step-by-step explanation:

Given:

S₁₋₄= 4/2(2a+3d)=4a+6d= 30

⇒ 2a+3d=15

S₄₋₇= S₇ - S₃= 7/2(2a+6d)- 3/2(2a+2d)= 7a+21d - 3a - 3d= 4a+18d=66  

⇒ 2a+9d= 33

Comparing the 2 equations:

beanburito

step-by-step explanation:

homozygous. one is homozygous, while two is heterozygous.