A. Find the common factors of 12 and 20. [2marks]
2. Hence find the highest common factor(HCF) of 12 and 20.
[1mark)
A school purchases workbooks in packs of 25 and text books in packs of 15.
The school needs exactly the same number of workbooks as textbooks so
they can be paired up for the students. What is the minimum number of each
pack that must be bought so that all the books are paired? You must show all
[3marks]
of your working

a. Common factors of 12 and 20 = 2, 2

2. Highest common factor of 12 and 20 = 4

3 packs of workbooks and 5 packs of text books to be purchased.

Step-by-step explanation:

a.) To find the common factors of 12 and 20:

First of all, let us find the factors of 12 and 20

12 = 2 2 3

20 = 2 2 5

The common factors are underlined above i.e. 2, 2.

2. The highest common factor between 12 and 20 is 2 2 = 4

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Workbooks are in packs of 25

Textbooks are in pack of 15

The school needs exactly same number of workbooks and textbooks.

And we have to find such least number.

This least number can simply be calculated by finding the LCM (Least Common Multiple).

LCM of two numbers p and q is the minimum number which is completely divisible by both the numbers p and q.

Let us find LCM of 25 and 15 using factorization method:

15 = 3 5

25 = 5 5

The common part is considered only once:

So LCM =  3 5 5 = 75

Hence, number of packs of workbooks to be bought =

number of packs of textbooks to be bought =

So, the answer are:

a. Common factors of 12 and 20 = 2, 2

2. Highest common factor of 12 and 20 = 4

3 packs of workbooks and 5 packs of text books to be purchased.

a .4y4

hope this !

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)