Given ΔQXY with RS || XY Prove XR/RQ = YS/SQ statements: 1. RS || XY 2. ∠1=∠3, ∠2=∠4 3. ΔQXY ~ΔQRS 4. XQ/RQ = YQ/SQ 5. XQ=XR+RQ, YQ=YS+SQ 6. XR+RQ/RQ = YS=SQ/SQ 7. XR/RQ = YS/SQ

It can be proved by:

The two triangles are similar and the ratio of corresponding sides are equal.

Step-by-step explanation:

We are given a ΔQXY which has a line RS inside it such that RS || XY.

To prove:

First of all, let us have a look at the ΔQXY and ΔQRS as per the given question figure:

1. ∠1=∠3 (Because sides XY || RS and ∠1, ∠3 are corresponding angles)

2. ∠2=∠4 (Because sides XY || RS and ∠2, ∠4 are corresponding angles)

3. ∠Q is common to both the triangles.

So, all the three angles are equal to each other, hence the two triangles are similar:

If two triangles are similar, then ratio of their corresponding sides is also equal.

Subtracting 1 from both the sides:

Now, it is clearly observable that:

XQ - RQ = XR and

YQ - SQ = YS

Putting the values in above equation:

Hence proved.

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

take it another