You draw two cards without replacement from a standard deck of 52 cards. What is the probability of drawing a six then a seven?

4/663

Step-by-step explanation:

There are 4 6s and 4 7s, so the probability of getting a 6 on the first draw is 4/52 or 1/13. After the first draw there are 51 cards remaining (given your no replacement assumption), and there are 4 7s, so the probability of getting a 7 is 4/51.

The overall probability is

1/13 x 4/51 = 4 / 663

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.

a

step-by-step explanation:

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