Can u guys PLEASE answer this question ASAP. A line passes through the point (2,4) and has a gradient 2. Find the y-coordinate of the point on the line when x=3

y=2

Step-by-step explanation:

Make an equation of straight line by using the formula :y= mx+c

put the x-value of point (2,4) which is 2 and the gradient,m which is 2 into the straight line equation:

y=2x +c

So you need to find the y-intercept to complete the equation, therefore:

when y=0,

0=2(2)+c

c=-4

next the question ask to find the y-coordinate when x =3, therefore you just need to replace x in the equation with 3:

y=2(3)-4

y=4

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2