A statistician calculates that 9% of Americans are vegetarians. If the statistician is correct, what is the probability that the proportion of vegetarians in a sample of 471 Americans would be greater than 8%

The probability that the proportion of vegetarians in a sample of 471 Americans would be greater than 8% is P=0.776.

Step-by-step explanation:

We have to calculate a probability that a sample of n=471 has a proportion greater than 8%, given that the population proportion is 9%.

First, we have to calculate the parameters of the sampling distribution of the proportions:

Now, we can calculate the probability using the z-score:

Then, the probability is:

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.