g You have drawn a simple random sample of 68 college students, asking each student their grade point average (GPA). Each individual draw is normally distributed with a standard deviation of 0.2. You obtain a sample mean grade point average of 2.89. Calculate the upper confidence limit of a 92% confidence interval for the population mean of grade point average. If necessary, round your answer to four decimal places. HINT: For a confidence interval of [a, b] we refer to "a" as the "lower confidence limit" and we refer to "b" as the "upper confidence limit".

The upper confidence limit of a 92% confidence interval for the population mean of grade point average is 2.93.

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find the margin of error M as such

In which is the standard deviation of the population and n is the size of the sample.

The upper end of the interval is the sample mean added to M. So it is 2.89 + 0.04 = 2.93.

The upper confidence limit of a 92% confidence interval for the population mean of grade point average is 2.93.

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

answer: 40.95

step-by-step explanation: