What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)? vx
y= 2x +33
y=*x + 36
y = 4x - 16
y = 4x + 16

y = 4x + 16

Step-by-step explanation:

Two lines are parallel if they have the same slope. The slope of the line y - 1 = 4(x + 3) is 4. Using slope y-intercept form, a line with slope 4 which passes through the point (4, 32) satisfies:

y = m*x +b

32 = 4*4 + b

b = 32 - 4*4

b = 16

Therefore, the equation is y = 4x + 16

the answer is b