You might need: A circle is centered at J(3,3) and has a radius of 12.

Where does the point F(-6, -5) lie?

Choose 1

Step-by-step explanation:

The equation of this circle is (x - 3)^2 + (y - 3)^2 = 12^2.

Let's substitute the coordinates of the given point and compare the results to the above equation:  do they produce a correct statement?

(-6 - 3)^2 + (-5 - 3)^2 = ?

9^2 + 8^2 = 145

Because r = 12, the above result would need to be 144, not 145, if the given point were actually on the circle.  We must conclude that (-6, -5) lies just outside the circle.

81 + 64 = 144  

b i think

step-by-step explanation:

not really sure

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.