Is domain of f(x, y) = 1 + (4 -y^2)^1/2 open, closed or neither

is it bounded or unbounded?

Closed and Bounded.

Step-by-step explanation:

Hi there!

1) Let's start by finding the values in which the function is defined. Remember that this can be rewritten:

Since every quadratic root are defined for values 0  then, this help us to understand that we need calculate what interval this Domain is:

2) Graphically speaking, the domain is closed. For the values -2 and 2 are included, and bounded.

Bounded functions have all of their points contained by some circle origin centered. Check it out below.