A randomly selected sample of n =51 men in Brazil had an average lifespan of 59 years. The standard deviation was 10 years. Calculate a 98% confidence interval for the average lifespan for all men in Brazil.

The 98% confidence interval would be given by (55.639;62.361)    

Step-by-step explanation:

Information given

represent the sample mean

represent the sample deviation

represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

  (1)

The degrees of freedom are given by:

The Confidence is 0.98 or 98%, the significance would be and ,and the critical value would be

And replacing we got:

The 98% confidence interval would be given by (55.639;62.361)    

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

answer: 193

explanation:

200-7 = 193