Can you do this for me 3x+y=10, 2x^2+y^2=19

1 , 29/11

Step-by-step explanation:

3x+y = 10 (1)

2x² +y² = 19 (2)

3x+y= 10

y = 10-3x

substituting the value of y in 2nd equation

2x² + y² = 19

2x² + (10-3x)² = 19

2x² + 100 + 9x² - 60x -19 = 0

11x² - 60x +81 = 0

11x² - 33x - 27x + 81 = 0

11x( x-3) - 27(x-3) = 0

(x-3)(11x-27) = 0

x = 3, 27/11

substituting x value on first equation

x= 3 x= 27/11

y= 10-3(3) y= 10 - 81/11

= 10-9 = (110-81)/11

= 1 = 29/11

Hope it helps...

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)