Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!

 h = -(16t + 3)(t - 2)

               h(0) = 6

               h(1) = 19

               h(2) = 0

Step-by-step explanation:

Factor the equation by finding two numbers whose

product = a×c and sum = b, then replace the b value with those two numbers and factor the equation.

h = -16t² + 29t + 6      

 a=-16   b=29   c=6           a×c = -96      b = 29      

                                      32 × -3 = 96          32 + (-3) = 29

h = -16t² + 32t    -3t + 6

h = -16t(t - 2)      -3(t - 2)

h = (-16t - 3) (t - 2)

h = -(16t + 3)(t - 2)

h(0) = -[16(0) + 3] [0 - 2]

      = -(3)(-2)

      = 6  

h(1) = -[16(1) + 3] [1 - 2]

      = -(19)(-1)

      = 19  

h(2) = -[16(2) + 3] [2 - 2]

      = -(35)(0)

      = 0  

c

step-by-step explanation: