Mathematics, 24.06.2020 18:01, hello1942

Use z scores to compare the given values. The tallest living man at one time had a height of 252 cm. The shortest living man at that time had a height of 79.2 cm. Heights of men at that time had a mean of 176.74 cm and a standard deviation of 8.06 cm. Which of these two men had the height that was moreâ extreme?

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The more extreme height was the case for the shortest living man at that time (12.1017 standard deviation units below the population's mean) compare with the tallest living man (at that time) that was 9.3374 standard deviation units above the population's mean.

Step-by-step explanation:

To answer this question, we need to use standardized values, and we can obtain them using the formula:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

Where

x is the raw score we want to standardize. $\\ \mu$ is the population's mean. $\\ \sigma$ is the population standard deviation.

A z-score "tells us" the distance from $\\ \mu$ in standard deviation units, and a positive value indicates that the raw score is above the mean and a negative that the raw score is below the mean.

In a normal distribution, the more extreme values are those with bigger z-scores, above and below the mean. We also need to remember that the normal distribution is symmetrical.

Heights of men at that time had:

$\\ \mu = 176.74$ cm. $\\ \sigma = 8.06$ cm

Let us see the z-score for each case:

Case 1: The tallest living man at that time

The tallest man had a height of 252 cm.

Using [1], we have (without using units):

$\\ z = \frac{x - \mu}{\sigma}$

$\\ z = \frac{252 - 176.74}{8.06}$

$\\ z = \frac{75.26}{8.06}$

$\\ z = 9.3374$

That is, the tallest living man was 9.3374 standard deviation units above the population's mean.

Case 2: The shortest living man at that time

The shortest man had a height of 79.2 cm.

Following the same procedure as before, we have:

$\\ z = \frac{x - \mu}{\sigma}$

$\\ z = \frac{79.2 - 176.74}{8.06}$

$\\ z = \frac{-97.54}{8.06}$

$\\ z = -12.1017$

That is, the shortest living man was 12.1017 standard deviation units below the population's mean (because of the negative value for the standardized value.)

The normal distribution is symmetrical (as we previously told). The height for the shortest man was at the other extreme of the normal distribution in $\\ 12.1017 - 9.3374 = 2.7643$ standard deviation units more than the tallest man.

Then, the more extreme height was the case for the shortest living man (12.1017 standard deviation units below the population's mean) compare with the tallest man that was 9.3374 standard deviation units above the population's mean.

answered: Guest

You must find the surface of the block therefore 98187 dived by 5628 = 583m squared

answered: Guest

i think it would be 42cm

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Use z scores to compare the given values. The tallest living man at one time had a height of 252 cm....